Question

The length of the sides of a triangle are 5 cm, 12 cm and 13 cm and a parallelogram made
on the base of 13 cm such that Area of triangle equal to area of parallelelogram then find
its height corresponding to the base of 13 cm.​

Answer 1

here we use formula for area of parallelogram I,e,

B into H

Answer 2

Given data

Consider ABC is a Triangle

length of triangle sides are AB=5 , BC=13 , AC=12

Therefore

Area of Triangle = √{S(S-A)(S-B)(S-C)} , S=(A+B+C)/2

Area of Triangle = 30cm^2

Given data that is

AREA OF TRIANGLE = AREA OF PARALLELOGRAM

30= 1/2× BASE× HEIGHT

30=1/2×BC× HEIGHT

30=1/2×13×HEIGHT

HEIGHT =(30×2)/13

HEIGHT= 4.6 cm