the length of the sides of a triangle are 5cm,12cm and 13cm.find the length of perpendicular from the opposite vertex to the side whose length is 13cm
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Area Of Triangle = Square Root Of (S(S-A)(S-B)(S-C))
Now S = 5+12+13/2 = 15
Now Simply Area = √(15*10*3*2)
Area = √ (900)
Area = 30
Now Area Of Triangle = 1/2*Base*Height
Now Base = 13
Now
1/2*13*Height = 30
13*Height = 30 *2
13*Height = 60
Height = 60/13 = 4.61 cm
Now S = 5+12+13/2 = 15
Now Simply Area = √(15*10*3*2)
Area = √ (900)
Area = 30
Now Area Of Triangle = 1/2*Base*Height
Now Base = 13
Now
1/2*13*Height = 30
13*Height = 30 *2
13*Height = 60
Height = 60/13 = 4.61 cm
Answered by
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hope this will help you
Area Of Triangle = Square Root Of (S(S-A)(S-B)(S-C))
Now S = 5+12+13/2 = 15
Now Simply Area = √(15*10*3*2)
Area = √ (900)
Area = 30
Now Area Of Triangle = 1/2*Base*Height
Now Base = 13
Now
1/2*13*Height = 30
13*Height = 30 *2
13*Height = 60
Height = 60/13 = 4.61 cm
Area Of Triangle = Square Root Of (S(S-A)(S-B)(S-C))
Now S = 5+12+13/2 = 15
Now Simply Area = √(15*10*3*2)
Area = √ (900)
Area = 30
Now Area Of Triangle = 1/2*Base*Height
Now Base = 13
Now
1/2*13*Height = 30
13*Height = 30 *2
13*Height = 60
Height = 60/13 = 4.61 cm
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