the length of the sides of a triangle are in the ratio 4:5:3 and its perimeter is 96 cm.find its area.
Answers
Answered by
21
let the side of the triangle be x
that becomes,
4x, 5x and 3x respectively
we know that,
4x+5x+3x = 96
12x=96
x= 96/12
x=8
the side now are 32, 40 and 24 respectively.
the semi perimeter is 48 (96/2)
now the area by heron's formula,
√s(s-a)(s-b)(s-c)
= √48*16*8*24
=√147456
=384
the area is 384 m²
that becomes,
4x, 5x and 3x respectively
we know that,
4x+5x+3x = 96
12x=96
x= 96/12
x=8
the side now are 32, 40 and 24 respectively.
the semi perimeter is 48 (96/2)
now the area by heron's formula,
√s(s-a)(s-b)(s-c)
= √48*16*8*24
=√147456
=384
the area is 384 m²
Debly:
Thank you
Hey you did not find area
Chech now, the area has been added
srry guys the area isnt 384m² but 384²cm
Answered by
9
4x+5x+3x=12x
Perimeter=96
X=96/12=8
Each side is...
4*8=32
5*8=40
3*8=24
Area=√[s(s-a)(s-b)(s-c)]
S=a+b+c/2
S=48
Area=√[48*16*8*24]
Area=384sqcm
Perimeter=96
X=96/12=8
Each side is...
4*8=32
5*8=40
3*8=24
Area=√[s(s-a)(s-b)(s-c)]
S=a+b+c/2
S=48
Area=√[48*16*8*24]
Area=384sqcm
Similar questions