the length of the sides of a triangle are in the ratio 4:5:3 and its perimeter is 96 cm.find its area.
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let the sides of the triangle be 4x, 5x and 3x respectively.
perimeter of triangle = sum of all the sides
96 = 4x+ 5x+ 3x
96 = 12x
96/12 = x
8 = x
hence, 4x = 4 × 8 = 32 cm
5x = 5 × 8 = 40 cm
3x = 3 × 8 = 24cm
semi-perimeter of triangle = perimeter/2
= 96/2
= 48 cm.
acc. to heron's formula,area of triangle = [48(48-32)(48-40)(48-24)]^{1/2}
= [404 cm]^{2}
perimeter of triangle = sum of all the sides
96 = 4x+ 5x+ 3x
96 = 12x
96/12 = x
8 = x
hence, 4x = 4 × 8 = 32 cm
5x = 5 × 8 = 40 cm
3x = 3 × 8 = 24cm
semi-perimeter of triangle = perimeter/2
= 96/2
= 48 cm.
acc. to heron's formula,area of triangle = [48(48-32)(48-40)(48-24)]^{1/2}
= [404 cm]^{2}
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23
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