the length of the sides of a triangle are integrals,and it area is also integer.One side is 21 and the perimeter is 48.Find the shortest side
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the three lengths are 9,18 and 21
namburiviswanath7:
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Answer:
Step-by-step explanation:
We have to solve the problem in this way:
We can say the three sides as a, b, c
a+b+c: 48
One side is also given is 21
A+b+21: 48
A+b: 48-21: 27
We can divide it into 2 parts
As a+b: 27
Then 10+17: 27so
The shortest side is 10
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