the length of the sides of the triangle are 16cm , 23cm and 31 cm . if a perimeter of a similar triangle is 280cm . find the length of that triangle 's longest side
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2
Answer:
8 cm.
Step-by-step explanation:
Let △ABC and △DEF be two similar triangles of perimeters P
1
and P
2
respectively.
Also, let AB=12 cm, P
1
=30 cm and P
2
=20 cm.
Then,
DE
AB
=
EF
BC
=
DF
AC
=
P
2
P
1
[∵ Ration of corresponding sides of similar triangles is equal to the ratio of their perimeters]
⇒
DE
AB
=
P
2
P
1
⇒
DE
12
=
20
30
⇒ DE=
30
12×20
cm=8cm
Hence, the corresponding side of the second triangle is 8 cm
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