the length of the sides of the triangle are in the ratio 4 is to 5 is 26 and its perimeter is 150 cm find the area of the triangle and the height corresponding to the longest side
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Question-
The length of the sides of the triangle are in the ratio 4 : 5 : 6 and its perimeter is 150 cm. Find the area of the triangle and the height corresponding to the longest side.
Answer-
Let the unknown part of the side be x. Then,
4x + 5x + 6x = 150cm
⇒ 15x= 150cm
⇒ x = 150/15 cm
⇒ x = 10 cm
- 4x = 4 × 10 = 40 cm
- 5x = 5 × 10 = 50 cm
- 6x = 6 × 10 = 60 cm
s = a + b + c ÷ 2 = 40 + 50 + 60 ÷ 2 = 150 ÷ 2 = 75 cm
Area using Heron's formulae-
√s(s - a)(s - b)(s - c) cm²
= √75(75 - 40)(75 - 50)(75 - 60) cm²
= √75 × 35 × 25 × 15 cm²
= √(3 × 5 × 5) × (5 × 7) × (5 × 5) × (3 × 5) cm²
= 3 × 5 × 5 × 5√7 cm²
= 375√7 cm²
The longest side = 60 cm
Unknown height corresponding to the longest side = h
Then,
Area = 1/2 × base × height
⇒ 375√7 cm²= 1/2 × 60 cm × h
⇒ 375√7 cm²= 30h
⇒ h = 375√7 cm²/30 cm
⇒ h = 25√7/2 cm
Area = 375√7 cm²
Height corresponding to the longest side = 25√7/2
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