the length of the sides of triangular park are 90m,70m and 40m find its area. (use root5=2.24
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Solution -
Area of a triangle whose three sides are given is given by Heron's formula.
A = sqrt (s (s - a) ( s - b) (s - c))
Where s is the half perimeter.
s = (a + b + c) / 2
Given: a = 40m, b = 90m, c = 70m
s = (40 + 90 + 70) / 2
= 200/2
= 100 m
Area of the triangle A = sqrt (s (s - a) ( s - b) (s - c))
= sqrt (100 * (100 - 40) * (100 - 90) * ( 100 - 70))
= sqrt ( 100 * 60 * 10 * 30)
= 10 sqrt (18000)
= 10 sqrt (3600 * 5)
= 10 * 60 * sqrt 5
= 10 * 60 * 2.24
= 1344 sq. m
Area of the triangular garden = 1344 sq. m
Area of a triangle whose three sides are given is given by Heron's formula.
A = sqrt (s (s - a) ( s - b) (s - c))
Where s is the half perimeter.
s = (a + b + c) / 2
Given: a = 40m, b = 90m, c = 70m
s = (40 + 90 + 70) / 2
= 200/2
= 100 m
Area of the triangle A = sqrt (s (s - a) ( s - b) (s - c))
= sqrt (100 * (100 - 40) * (100 - 90) * ( 100 - 70))
= sqrt ( 100 * 60 * 10 * 30)
= 10 sqrt (18000)
= 10 sqrt (3600 * 5)
= 10 * 60 * sqrt 5
= 10 * 60 * 2.24
= 1344 sq. m
Area of the triangular garden = 1344 sq. m
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area of scalene triangle by heron's formula
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