the length of the triangle are in ratio 3:4:5 and it's perimeter is 60 cm find the perimeter of the triangle whose vertices are the mid points of the sides of the given triangle.
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1
take 3 as x,4 as y,5 as z
total length of triangle=3+4+5=12
perimeter=60
x=3÷12×60=15
y=4÷12×60=20
z=5÷12×60=25
then the sides are 15,20,25
total length of triangle=3+4+5=12
perimeter=60
x=3÷12×60=15
y=4÷12×60=20
z=5÷12×60=25
then the sides are 15,20,25
Answered by
0
X=3,Y=4,Z=5
Perimeter=60
Total=3+4+5=12
X=3/12 ✖ 60=15
Y=4/12 ✖ 60=20
Z=5/12 ✖ 60=25.
Therefore
(X,Y,Z)=(15,20,25,)
Perimeter=60
Total=3+4+5=12
X=3/12 ✖ 60=15
Y=4/12 ✖ 60=20
Z=5/12 ✖ 60=25.
Therefore
(X,Y,Z)=(15,20,25,)
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