Math, asked by bmjadav46, 1 year ago

the length of the triangle are in ratio 3:4:5 and it's perimeter is 60 cm find the perimeter of the triangle whose vertices are the mid points of the sides of the given triangle.

Answers

Answered by sai3817
1
take 3 as x,4 as y,5 as z

total length of triangle=3+4+5=12

perimeter=60

x=3÷12×60=15

y=4÷12×60=20

z=5÷12×60=25

then the sides are 15,20,25
Answered by ASaiBhavya
0
X=3,Y=4,Z=5
Perimeter=60
Total=3+4+5=12
X=3/12 ✖ 60=15
Y=4/12 ✖ 60=20
Z=5/12 ✖ 60=25.
Therefore
(X,Y,Z)=(15,20,25,)
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