Question

The length of the wall of a trapezoidal field ABCD (see Fig. 11.9) is
160 m. If BC = 60 m, CD = 24 m, and AD = 40 m, find the area of this
field. Note that the side AB is perpendicular to the parallel sides AD
and BC.

Answer 1

Answer:

Area of trapezium = $\frac{AD+BC}{2}h$

Step-by-step explanation:

Height AB = 160-(60+24+40) = 160-124=26

$=\frac{40+60}{2}\times26$

$=\frac{100}{2}\times26$

$=50\times26$

$=130$ sq m is the area of trapeziodal field