Question

the length of the wire of the potentiometer is 8 meters. what will be the value of the voltage gradient when 2 volts potential difference is applied at its ends

Answer 1

Answer:

given,

length of wire 8 meter

potential difference 2 volt

k = E/L = 2/8

k= 1 /4

k = o.25 volt meter

Answer 2

SOLUTION

GIVEN

The length of the wire of the potentiometer is 8 meters.

TO DETERMINE

The value of the voltage gradient when 2 volts potential difference is applied at its ends

EVALUATION

Here it is given that the length of the wire of the potentiometer is 8 meters.

Also 2 volts potential difference is applied at its ends

So by the given condition

D = The length of the wire of the potentiometer

= 8 meters

V = The potential difference is applied at its ends

= 2 volts

We know that voltage gradient is a difference in electrical potential across a distance or space.

More precisely voltage gradient is potential drop per unit length of wire.

Thus the required value of the voltage gradient

$\displaystyle \sf{ = \frac{V}{D} \: \: \: volt / meter }$

$\displaystyle \sf{ = \frac{2}{8} \: \: \: volt / meter }$

$\displaystyle \sf{ = \frac{1}{4} \: \: \: volt / meter }$

$\displaystyle \sf{ = 0.25 \: \: \: volt / meter }$

FINAL ANSWER

The value of the voltage gradient

= 0.25 volt / meter

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