Math, asked by shrimantra8848, 1 year ago

the length of three pieces of wire are in the ratio 10:15:8 if the length of the shortest piece of wire is 2.4m find the difference in the length of the other two pieces of wire

Answers

Answered by hemanth2261
2
given ratio=10:15:8
shortest piece of wire=8parts=2.4m=240cm
so 1part=240/8=30 cm
first piece of wire=10×30=300cm
second piece of wire=15×30=450 cm
difference of first and second piece of wire
=450-300=150 cm=1.5m
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