Question

the length of three sides of a triangle are 20 cm,16 cm and 12 cm . the area of the triangle is​

Answer 1

Answer:

Heya!!

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HERON'S FORMULA

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Area of a triangle of sides a , b & c is :

√( s(s-a)(s-b)(s-c) )

where s=(a+b+c)/2

ln given trangle , s=(20+12+16)/2=48/2=24

Thus area of given triangle =

√(24(24-20)(24-12)(24-16))

=√(24×4×12×8)

=√9216

=96

Thus area of triangle of sides 20cm ,12cm and 16cm is 96cm^2

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Answer 2

Answer:

a=20cm,b=16cm,c=12cm

this is right angle Triangle

s=a+b+c/2

=20+16+12/2

=48/2

=24cm

area of Triangle =root over s(s-a)(s-b)(s-c)

=24(24-20)(24-16)(24-12)

=24×4×8×12

=root over9216

=96 cm square