The length of two parallel sides of a trapezium are 3 cm and 4 cm. Distance between the two parallel sides is 2 cm. Find the area of trapezium.
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Let the two parallel sides of the trapezium be a cm and b cm.
Given that difference between the two parallel sides is 4 and the perpendicular distance(h) is 19
⇒a−b=4⟶(1)
We know that Area of Trapezium = 21×(a+b)×h
Substituting the values of h we get,
21×(a+b)×19=475
⇒(a+b)=19475×2
⇒a+b=50⟶(2)
Adding (1) and (2),
a−b=4
a+b=50
−2b=−54
b=254=27
Putting b=27 in (2) we get
a+27=50
a=50−27=23
Two parallel sides are 27 cm and 23 cm.
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Hope this Helps!!
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