Question

The length of two parallel sides of trapezium is 3.4 cm and 4.2 CM.
the distance between the parallel side is 12 cm .find the area.​

Answer 1

Answer:

The area of the trapezium is :-

$44.4 \: {cm}^{2}$

Step-by-step explanation:

We Have :-

Length of Parallel sides of trapezium = 3.4 cm and 4.2 cm

Height = 12 cm

To Find :-

Area of the Trapezium

Formula Used :-

Area of Trapezium =

$\dfrac{1}{2} \times \: ( \: sum \: of \: parallel \: sides \: ) \times height$

Solution :-

$area \: = \: \dfrac{1}{2} \times ( \: 3.2 + 4.2 \: ) \times 12 \\ \\ area \: = \dfrac{1}{2} \times 7.4 \times 12 \\ \\ area \: = 7.4 \times 6 \\ \\ area \: = 44.4 \: cm^{2}$

Answer 2

Answer:

$\huge \dag \Large\underline\frak \red{Given}$

• ↝ The length of two parallel sides of trapezium is 3.4 cm and 4.2 CM.
• ↝ The distance between the parallel side is 12 cm

$\huge \dag \Large \underline\frak \red{To \: Find }$

• ↝ Area of Trapezium

$\huge\dag \Large\underline\frak \red{Using \: Formula}$

${: \implies\sf \pink{Area \: of \: Trapezium } = \purple {\dfrac{1}{2} \times Sum \:of\: Parallel \:Side \times Height}}$

$\huge \dag \Large \underline \frak \red{Solution}$

✒ Here we know that the two parallel side of Trapezium and the Height of Trapezium also.

So,

${:\implies \sf \pink{Area }= \purple {\dfrac{1}{2} \times (3.4 + 4.2)cm \times 12 \: cm}}$

${: \implies \sf \pink{Area} = \purple { \dfrac{1}{2} \times 7.6 \: cm\times 12 \: cm}}$

$: \implies \sf \pink{Area} = \cancel \purple {\dfrac{91.2 }{2} } {\purple{cm}^{2}}$

$: \implies \sf \pink{Area }= \purple{45.6 \: {cm}^{2} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \Large\underline{\boxed{\frak\purple{Area} = \sf\pink{ 45.6 \: {cm}^{2} }}}$

$\huge \dag \Large \underline\frak \red{Therefore}$

• ↝ The of Trapezium is 45.6 cm²