The length of two sides of a parallelogram are 17cm and 12cm. One of its dioganal is 25cm long. Find the area of the parallelogram. Also find the length of altitude from vertex on the side of length 12cm?
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we know Diagonal of a llgm divides the figure into two equal triangles...
Therefore , In ∆ABC
p = 17+12+25
= 54cm
s = p/2 = 54/2 = 27cm
Thus, using heron's formula
area(∆ABC) = √s(s-a)(s-b)(s-c)
= √27(27-17)(27-12)(27-25)
= √3×9×5×2×5×3×2
= 3×2×5×3
= 90cm²
Area of IIgm = 90×2 = 180cm²
Show me the figure for question 2...
Therefore , In ∆ABC
p = 17+12+25
= 54cm
s = p/2 = 54/2 = 27cm
Thus, using heron's formula
area(∆ABC) = √s(s-a)(s-b)(s-c)
= √27(27-17)(27-12)(27-25)
= √3×9×5×2×5×3×2
= 3×2×5×3
= 90cm²
Area of IIgm = 90×2 = 180cm²
Show me the figure for question 2...
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