Question

. The length of two sides of a right angled triangle are 12m and 16m. Find its hypotenuse.
Please tell step by step ​

Answer 1

Answer

Given\large \tt \green{Given}Given

☞ Length of two sides of triangle are:-

12 metre

16 metre

ToFind\large \tt \red{To \: Find}ToFind

☞Length of hypotenuse

FormulaUsed\large \tt \blue{Formula \: Used}FormulaUsed

☞ Pythagoras Theorm

☞

h2=p2+b2{h}^{2} = {p}^{2} + {b}^{2}h

2

=p

2

+b

2

Solution\large \tt \orange{Solution}Solution

☞

h2=p2+b2{h}^{2} = {p}^{2} + {b}^{2}h

2

=p

2

+b

2

h2=122+162{h}^{2} = {12}^{2} + {16}^{2}h

2

=12

2

+16

2

h2=144+256{h}^{2} = 144 + 256h

2

=144+256

h2=400{h}^{2} = 400h

2

=400

h=200{h} = \sqrt{200}h=

200

h=20×20h = \sqrt{20 \times 20}h=

20×20

h=20h = 20 o

h = 20

Answer 2

Let:

$\tt{\longrightarrow a = 12m}$

$\tt{\longrightarrow b = 16m}$

$\tt{\longrightarrow c = Hypotenuse}$

Pythagoras Theorem:

We are going to find the Hypotenuse by applying Pythagoras Theorem. It says that:

In a right angled triangle, the square of Hypotenuse is equal to sum of square of its other two sides.

$\tt{\longrightarrow (Hypotenuse)^2 = (First\:Side)^2+(Second\:side)^2}$

Solution:

$\tt{\longrightarrow c^2 = a^2+b^2}$

$\tt{\longrightarrow c^2 = 12^2+16^2}$

$\tt{\longrightarrow c^2 = 144+256}$

$\tt{\longrightarrow c^2 = 400}$

$\tt{\longrightarrow c = \sqrt{400}}$

$\tt{\longrightarrow c = 20}$

Hence, the length of Hypotenuse is 20m.

Know more:

• The side opposite to the right-angled side is called as Hypotenuse.
• The right-angled side is called as Perpendicular.
• The side which is adjacent to right-angled side is called as base.