Question

the length of two sides of a triangle is 13 and 16 cm. between which two numbers can the third side fall???answer fast please

Answer 1

Answer: between 3cm and 29cm

Step-by-step explanation:

The three sides of a triangle must satisfy the following condition:

(a-b) < c < (a+b)

a=16cm

b=13cm

Hence, c should lie in between (a-b) and (a+b).

That is between

a-b= 16-13=3

and

a+b=16+13=29

Answer 2

$\huge\mathfrak{Solution:}$

Given that :-

The length of two sides of a triangle is 13 and 16 cm.

To find :-

Two numbers in which third side can fall.

As we know that the sum of two sides in a triangle, is always greater than third side.

First value

$16 - 13 = 3$

Second value

$16 + 13 = 29$

$\boxed{Two\:numbers\:are:\: 3,\:29}$