Question

The length of two sides of a triangles are 8cm and 10cm and the angle between them is 40° calculate its what is the area of the triangle with sides of the length but angle between them 140°

Answer 1

Answer:

40/140=8/x and 40/140=10/x

x=140/40×8 and x=140/40×10

X=70 and X=35

so area=1/2×70×35

35×35

1225

Step-by-step explanation:

Mark me brainliest

Answer 2

Answer:-

If the angle between the sides is 140° sin 140 = sin(180 – 40) = sin 40 The area of the triangles will be same.

Solution:-

1. Area of the triangle = 1 2 12x 10 x AD In ∆ ABD sin 40 = A D A B ADAB AD = AB x sin 40 = 8 sin 40 = 8 x 0.6428 = 5.1424 cm
2. ∴ Area = 1 2 x 10 x A D 12x10xAD = 1 2 x 10 x 5.14 12x10x5.14. = 25.7 cm2