Question

The length of two wires are in the ratio 3:4.
Ratio of the diameters is 1:2; young's modulus
of the wires are in the ratio 3:2; If they are
subjected to same tensile force, the ratio of
the elongation produced is​

Answer 1

Answer:

Y=Fl/Ae=2:1

A directly proportional to d square

e1/e2=3/4×4/1×2/3=2:1

Answer 2

Explanation:hope it helps