Question

the length of vector, A=3i+4j+9k in yz plane is​

Answer 1

Answer:

4j+9k=square root of4+9=under root 97and I is not considered. because I cap is absent in yz plane

Answer 2

Answer:

$\sqrt{97}$

Explanation:

We are given that a vector A=$3\hat{i}+4\hta{j}+9\hat{k}$

We have to find the length of vector in YZ-plane

In order to find the value of length we will find the value of magnitude because magnitude is also called length of vector

Using formula of magnitude of a vector r=$x\hat{i}+y\hta{j}+z\hat{k}$

magnitude of r=$\sqrt{x^2+y^2+z^2}$

When we take YZ-plane then x=0

y=4 and z=9

Therefore, the length of vector=$\sqrt{4^2+9^2}$

The length of vector=$\sqrt{16+81}=\sqrt{97}$

Hence, the length of vector A in yz plane =$\sqrt{97}$