the length of wall is 5 less than two times its breadth . what is the perimeter of the wall if its breadth is b meter - math in introduction to algebra
Answers
Answered by
24
breadth = b m
length = ( 2 b ) - 5
= 2b - 5
perimeter of rectangle = 2 ( l + b )
= 2 [ ( 2b -5 ) + b ]
= 2 ( 2b + b - 5 )
= 2 ( 3b - 5 )
= 6b - 10 m
perimeter is 6b - 10 m
plz mark as the brainliest
length = ( 2 b ) - 5
= 2b - 5
perimeter of rectangle = 2 ( l + b )
= 2 [ ( 2b -5 ) + b ]
= 2 ( 2b + b - 5 )
= 2 ( 3b - 5 )
= 6b - 10 m
perimeter is 6b - 10 m
plz mark as the brainliest
rajkumar70:
join me
no i will not
why
give me answer
no
as your wish
Answered by
0
Answer:
breadth of wall=b metre
length of wall= 2b-5 metre
perimeter of the wall= 2(l+b)
=2(2b-5+6) metre
=2(3b-5) metre
= 6b-10
Similar questions