The length of wire is doubled by pulling it find the new resistance when old resistance is 6 ohm??
please answer
Answers
Answered by
0
Rnew = ρl/4A
By using eqaution (1) we can simplify the above equation as
Rnew = R/4
Rnew = 6/4
Rnew = 1.5 Ohms
Answered by
0
Answer:
R = 6 Ohms -------(1)
A = 2A
L = l/2
Wire is doubled so,
Area (A) = 2A
length (l) = l/2
New Resistance
Rnew = ρl/4A
By using eqaution (1) we can simplify the above equation as
Rnew = R/4
Rnew = 6/4
Rnew = 1.5 Ohms
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