Question

the length of wire is increased by 0.1% of its initial length, how many percentage by its resistance will increase​

Answer 1

Assume initially,

Length=l

Cross−sectionarea=A

Resistance=R

After increase, Length=l′

Cross-sectional area=A′

Resistance=R′

l′=l+0.1%l=l+1000.1l=1.001l

But, volume remains same.

V′=V⇒A′l′=Al

⇒A′(1001)L=Al

∴A′=1.001A

New Resistance(R′)=ρA

please mark as branliest