Question

The length or a rectangle exceeds its breadth by 15 cm. If perimeter of
rectangle is 98 cm, find the dimensions of rectangle. Also, find the area of rectangle.

solve= let the breadth of rectangle be =
$xcm$
Length of rectangle=
$x + 15cm$
Now,
perimeter of rectangle= 98cm
2(length+ breadth) =98cm
=2(x+15+x) =98cm
= 2x+30+2x=98
= 4x+30=98
= 4x=98-30
= 4x=68
= x =68/4
= x=17


Breadth of rectangle=xcm=17cm
length of rectangle=x+15cm
=17+15cm
=32cm
Area of rectangle=length×breadth
= 32×17=544cm sq.

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Answer 1

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Answer 2

Answer:

solve= let the breadth of rectangle be =

$xcm$

Length of rectangle=

$x + 15cm$

Now,

perimeter of rectangle= 98cm

2(length+ breadth) =98cm

=2(x+15+x) =98cm

= 2x+30+2x=98

= 4x+30=98

= 4x=98-30

= 4x=68

= x =68/4

= x=17

Breadth of rectangle=xcm=17cm

length of rectangle=x+15cm

=17+15cm

=32cm

Area of rectangle=length×breadth

= 32×17=544cm sq.

Step-by-step explanation:

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