Question

the length pf shadow of 5m high pole at the certain time of a day is 7.5 metre what will be the height of of another pole whose shadow at the same time is 90 m long​

Answer 1

Height of pole=AB=5m

Length of shadow of pole =BC=7.5 m

Length of shadow of tower=EF=90 m

In △ABC and △DEF

∠B=∠E=90∘ both 90∘ as both are vertical to ground

∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

So,DEAB=EFBC

⇒DE6=284

⇒DE=6×7=42 m

Hence the height of the tower is 42 m

Answer 2

Answer:

Height of tower will be 42 m.