the length rectangle is increased by 25% while breadth is diminished by 30% what is the impact of area.
Answers
Answered by
80
Let the length of the rectangle = x
Increasing 25%
= x + 0.25 = 1.25x
Length = 1.25x
Let the breadth of the
rectangle = y
diminished by 30%
= y - 0.3y = 0.7y
breadth = 0.7y
Area of rectangle= length x breadth
= (1.25x) (0.7y)
= 0.875xy
Change in Area --
xy - 0.875xy = 0.125xy
Percentage of area changed-
= 0.125xy÷xy*100
= 12.5 % .
Answer is 12.5% .
Increasing 25%
= x + 0.25 = 1.25x
Length = 1.25x
Let the breadth of the
rectangle = y
diminished by 30%
= y - 0.3y = 0.7y
breadth = 0.7y
Area of rectangle= length x breadth
= (1.25x) (0.7y)
= 0.875xy
Change in Area --
xy - 0.875xy = 0.125xy
Percentage of area changed-
= 0.125xy÷xy*100
= 12.5 % .
Answer is 12.5% .
Answered by
9
Answer:
12.5 % (decrease)
Step-by-step explanation:
Let the original length be 'l' and breadth be 'b'.
∴ Area = length * breadth
= lb
When length increases by 25% and breadth is diminished(decreased) by 30%,
length = l + 25% of l = l + (25/100)l
= l + 0.25l = 1.25l
breadth = b - 30% of b = b - (30/100)b
= b - 0.3b = 0.7b
∴ Area = (1.25l) * (0.7b) = 0.875lb
[As 0.875lb < lb, area is decreased]
∴ Change % = (lb - 0.875lb) / lb * 100%
= [ 0.125lb ] / lb * 100%
= (0.125) * 100%
= 12.5%
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