Question

the length wide the height of a cubiad are 12 cm , 13cm, and 15cm, . find the lateral surface area of a cubiad . ​

Answer 1

$\bf \: \underline{ Given} :$ ↴

$\sf \implies Length = 12\: cm$

$\sf \implies Breadth = 13\: cm$

$\sf \implies Height = 15 \: cm$

$\bf \: \underline{To \: find} :$ ↴

$\sf \implies Lateral \: surface \: area \: of \: cuboid.$

$\bf \: \underline{Formula \: to \: be \: used},$

$\boxed{ \sf \: Lateral \: surface \: area \: of \: cuboid = \red{2(LH +BH)}\: Sq.unit}$

$\sf \underline{Where},$

$\sf \bull \: \implies \:L = Length$

$\sf \bull \: \implies \:B = Breadth$

$\sf \bull \: \implies \:H = Height$

$\sf \: Therefore,$

$\sf \: \underline{Putting \: the \: values} \: :$

$\sf \implies \sf \: {2 \: (12 \times15 + 13 \times 15)}$

$\sf \implies \sf \: {2 \: (180 + 195)}$

$\sf \implies \sf \: {2 \: (375)}$

$\sf \implies \sf \: {2 \times 375}$

$\red{\sf \implies \sf \: {750} \: cm^{2}}$

$\underline{ \boxed{\pink{ \sf \: Hence \: lateral \: surface \: area \: of \: cuboid = 750\: cm^{2}}}}$

$\underline{\sf Some \: more \: information \: about \: Cuboid} :$

$\sf \: 1. \: Volume \: of \: cuboid : (Length \times Breadth \times Height) \: \underline{ Cubic \: units}$

$\sf \: 2. \: Diagonal \: of \: Cuboid : \sqrt{(L^{2} + B^{2} + H^{2}) }\: units$

$\sf\:3. \: Perimeter \: of \: cuboid : 4 \: (length + breadth + height)\:Sq.units$

$\sf \: 4. \: Total \: surface \: area : 2(LB +BH + HL)\: Sq.units$

$\sf \: 5. \: Lateral \: Surface \: area : 2 \: height \: (length + breadth) \: Sq.units$