Math, asked by thrishatshetty, 1 month ago

The length, width and height of a room are 825cm, 675cm, 450cm respectively. Write the correct integers for these three numbers​

Answers

Answered by Muskansolanki555
0

Step-by-step explanation:

To find the length of the longest tape which can measure the three dimensions of the room, we need to find the H.C.F of length, breadth and height of the room respectively.

Length of the room = 825 cm

Breadth of the room = 675 cm

Height of the room = 450 cm

Let us factorize all three given dimensions.

825 = 3 × 5 × 5 × 11

675 = 3 × 3 × 3 × 5 × 5

450 = 2 × 3 × 3 × 5 × 5

Hence, 3, 5 and 5 are the common prime factors here.

So, H.C.F =3 × 5 × 5

H.C.F = 75 cm

Therefore, we need 75 cm the longest tape to measure the three dimensions of the room

Answered by rekha971950
0

Answer:

To find the length of the longest tape which can measure the three dimensions of the room, we need to find the H.C.F of length, breadth and height of the room respectively.

Length of the room = 825 cm

Breadth of the room = 675 cm

Height of the room = 450 cm

Let us factorize all three given dimensions.

825 = 3 × 5 × 5 × 11

675 = 3 × 3 × 3 × 5 × 5

450 = 2 × 3 × 3 × 5 × 5

Hence, 3, 5 and 5 are the common prime factors here.

So H.C.F =3 × 5 × 5

H.C.F = 75 cm

Therefore, we need 75 cm the longest tape to measure the three dimensions of the room.

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