Question

The length width height of the room are 7 ,8, 9 m respectively . what is the total area of the wall? ​

Answer 1

Given :

Length of the room = 7 m.

Width of the room = 8 m.

Height of the room = 9 m.

To find :

Total area of the wall.

Solution :

Length = 7 m.

Width = 8 m.

Height = 9 m.

We know,

${\boxed{\green{\bold{Total\:area\: of\: the\:wall=2(Length+Width)\times\: Height}}}}$

$\implies\sf{Total\:area\:of\: the\:wall=2(7+8)\times\:9\:m^2}$

$\implies\sf{Total\:area\:of\: the\:wall=2\times\:15\times\:9\:m^2}$

$\implies\sf{Total\:area\:of\: the\:wall=270\:m^2}$

Therefore the total area of the wall is 270 m².

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More Information :-

✪ Cuboid ✪

1. Total surface area of cuboid =

2(l×b + l×h + w×h)

2. Diagonal of cuboid =

$\sqrt{l^2+w^2+h^2}$

3. Volume of cuboid =

Length × Width × Height

[ where l = length ,w = width, h = Height]

✪ Cube ✪

1. TSA of cube = 6a²

2. Diagonal of cube = a√3

3. Volume of cube = a³

[ Where a = side ]

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Answer 2

Answer:

area of a room = lenght *breadth*height

area = 7*8*9=509

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