The lengthand the breadth of arectengular field are in the ratio 5:3. if its perimeter is 128m, find the dimensions of the field
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Perimeter of the rectangle = 128 m. Sum of adjacent sides of the rectangle = 128/2 = 64 m. 5x+3x = 8x = 64, or x = 8. Hence length of field = 5*8 = 40 m and width of field = 3x = 3*8 = 24 m.
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Answer:
128÷2=64
5x+3x=8x
64÷8 =8
5x=8*5=40m
3x=8*3=24m
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