Question

The lengths a triangle are x+1 ,2x+1,x+1 find it's area

Answer 1

Step-by-step explanation:

a=x+1

b=2x+1

c=x+1

s=(a+b+c)/2=(x+1+2x+1+x+1)/2=(4x+3)/2

Area

=√{s(s-a)(s-b)(s-c)}

=√{(4x+3)/2}{

$\sqrt{ \frac{4x + 3}{2}( \frac{4x + 3}{2} - (x + 1))( \frac{4x + 3}{2} -( 2x + 1 ))( \frac{4x + 3}{2} - (x + 1)) }$