Question

The lengths (in cm) of parallel sides of a trapezium are 2x and 3x -1, and the distance between
the parallel sides is x +1. If the area of the trapezium be 28 cm, find the smaller of the two
parallel sides.​

Answer 1

Step-by-step explanation:

height =x+1

2 parallel sides are 2x and 3x-1

Area of trapezium = 1/2×(Sum of parallel sides) ×height

28=1/2×(2x+3x-1)× x+1

x=3

then, 1 parallel side= 2x=6

Another parallel side is x+1=8

Answer 2

Step-by-step explanation:

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