the lengths of 2500 bolts, x mm, are summarised by sigma (x-40) = 875. find the mean length of the bolts
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Angles of triangle xᵒ(x−20), (x-40) О
Now, sum of angles = 180° (ASP of A)
⇒ x + (x-20) + (x-40) = 180
⇒ 3x-60= 180
3x 240
⇒x=80
.. 1st angle, x° = = 80
2nd angle (x-20) = 80-20 = 60°
3rd angle (x-40) = 80-40 = 40°.
I Hope it will help u
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