Question

The lengths of a diagonals of a rhombus are 24cm and 10cm then find each side of rhombus

Answer 1

96 sq.cm


The diagonals in a rhombus are perpendicular , and bisect each other

Given length of side is 10 cm and one diagonal as 12 cm we can find the length of other diagonal

From the above figure let DB be the 12 cm diagonal,now OB and OD are 6 cm

Now consider triangle AOB ,this is a right andled triangle and we know AB=10cm and OB=6cm ,using Pythagoras theorem we can find out lenth of OA as 8cm ,so length of diagonal AC is 2*8=16cm

Area of rhombus is product of diagonal divided by 2, 16*12/2=96 sq.cm
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Answer 2

Let ABCD IS rhombus of AC 24cm BD 10cm and diagonals intersect at O then AO+OC=24cm, from property diagonals bisect each other.so AO=OC=12cm.And BO=OC=5cm.Here AOB is is right angle triangle.From Pythagorean property square hypotenuse=side square+side square.then AB square=OBsquare+ OA square. From above AB square=5square+12square. ABsquare=25+144=169 that implies AB=13cm.so all sides are 13 cm.....If it is useful thank u mark as brainliest