The lengths of a diagonals of a rhombus are 24cm and 18cm respectively. Find the length of each side of the rhombus.
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Answered by
13
since ,
diagonal=24&18
half of that =12&9
the angle made by diagonals=90
.
. . by applying Pythagoras we get =side=144+81=225
side=root 225
=15
hope it helps
thank you
diagonal=24&18
half of that =12&9
the angle made by diagonals=90
.
. . by applying Pythagoras we get =side=144+81=225
side=root 225
=15
hope it helps
thank you
Answered by
4
We know that diagonals of a rhombus are perpendicular bisector of each other
Let us consider a rhombus ABCD
AC and BD are the diagonals
O is the midpoint
Now- in triangle AOB
AO^2+BO^2= AB^2
12^2+9^2=AB^2
144+81=AB^2
225 =AB^2
AB=15 cm
each side of the rhombus is 15 cm
Let us consider a rhombus ABCD
AC and BD are the diagonals
O is the midpoint
Now- in triangle AOB
AO^2+BO^2= AB^2
12^2+9^2=AB^2
144+81=AB^2
225 =AB^2
AB=15 cm
each side of the rhombus is 15 cm
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