Question

THE LENGTHS OF A DIAGONALS OF THE RHOMBUS ARE 16 cm and 12 cm respectively. find the length of each of its sides.

Answer 1

You don’t need to do anything more than using Pythagoras theorem to solve the above problem.
Hope this helps you... ✌

Answer 2

Answer:

$Length\:of \:each\:side\\in \:given\: Rhombus=10\:cm$

Step-by-step explanation:

$Let \: d_{1},\:and\:d_{2}\:are\\two\: diagonals\:of \: a \: Rhombus$

$Given ,\: d_{1}=16\:cm ;\\d_{2}=12\:cm;$

$Length\:of \:each\:side\\=\sqrt{\left(\frac{d_{1}}{2}\rihgt)^{2}+\left(\frac{d_{2}}{2}\rihgt)^{2}}$$=\sqrt{\left(\frac{16}{2}\rihgt)^{2}+\left(\frac{12}{2}\rihgt)^{2}}$

$=\sqrt{8^{2}+6^{2}}\\=\sqrt{64+36}\\=\sqrt{100}\\=\sqrt{10^{2}}\\=10$

Therefore,

$Length\:of \:each\:side\\=10\:cm$

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