Question

the lengths of a parallel sides of a trapezium are in the ratio of 3:5 and the distance between them is 10 cm. If the area of the trapezium is 120 cm2 find the lengths of its parallel sides.​

Answer 1

let the length of parallel sides be x

$area \: of \: trapezium \: = \frac{1}{2} \times (sum \: of \: parallel \: sides) \times height$

$= > 120 = \frac{1}{2} \times (3x + 5x) \times 10 \\ = > 120 = \frac{1}{2} \times (8x)10 \\ = > 120 = 40x \\ = > x = 3$

so parallel sides are 3x= 3×3=9cm

5x=5×3=15cm

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Answer 2

Answer:

Sorry for bad handwriting

Hope it will help

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