THE LENGTHS OF DIAGONAL OF RHOMBUS ARE IN RATIO 6:8 IF ITS PERIMETER IS 40 CM FIND THE LENGTH OF THE SHORTER DIAGONAL
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Answered by
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As we know that the perimeter of rhombus = 4*side
Here,
40 = 4*side
40/4 = side
10 side
then,
Let the length of diagonals be 6x and 8x
by pythagoras theorem,
10^2 = (6x/2)^2 +(8x/2)^2
100 = 9x^2 + 16x^2
100 = 25x^2
100/25 = x^2
4 = x^2
2= x
Now,
length of diagonals is:-
6*2 =12cm
and
8*2 =16cm
Length of shorter diagonal is 6x i.e. 12cm
i hope this will help you
-by ABHAY
Here,
40 = 4*side
40/4 = side
10 side
then,
Let the length of diagonals be 6x and 8x
by pythagoras theorem,
10^2 = (6x/2)^2 +(8x/2)^2
100 = 9x^2 + 16x^2
100 = 25x^2
100/25 = x^2
4 = x^2
2= x
Now,
length of diagonals is:-
6*2 =12cm
and
8*2 =16cm
Length of shorter diagonal is 6x i.e. 12cm
i hope this will help you
-by ABHAY
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0
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