Question

the lengths of diagonals of a rhombus are 16cm and 12cm. Find the length of each side.

Answer 1

the diagonal of rhombus bisect eachother
so , the length of half diagonal
will be
16/2=8cm and12/2= 6cm
now,
in that triangle ,
we should use Pythagoras thm
so 6*6+8*8=
=36+64
=100
the square root of 100 is 10
so length of each side of rhombus is 10cm

Answer 2

Question:-

The lengths of the diagonals of a rhombus are 16cm and 12cm. then find the length of the side of rhombus

Solution:-

we know that diagonal of rhombus,bisect each other in right angle ( 90° ).

we also know that all sides of rhombus are equal ( of equal length ).

so, now

Let rhombus is ABCD

Let, diagonal of rhombus

BD = 16 cm and AC = 12 cm

means,

OD = 8 cm and AO = 6 cm

By pythagorus theorem

To find length of AD ( and all side of rhombus )

=> (AD)² = (OD)² + (AO)²

=> (AD)² = (8)² + (6)²

=> (AD)² = 64 + 36

=> (AD)² = 100

=> AD = √100

=> AD = 10 cm

Hence length of all side of rhombus is 10 cm.

i hope it helps you.