Question

The lengths of diagonals of a rhombus is 10 cm and 24 cm .The perimeter of this special parallelogram rhombus is ? *​

Answer 1

Step-by-step explanation:

I have explained it in pic may it helps

Answer 2

Given :

• The diagonals of the rhombus = 10 cm and 24 cm.

To find :

• the perimeter of this special parallelogram rhombus.

Solution :

⇒ Let's find the Perimeter.

• Here, we have to find the length of AB to find the perimeter of the rhombus. As we can see AOB, looks like a right-angle triangle. So, to find the length of AB, we have to use the Pythagoras theorem.

$\sf \longrightarrow AB^2 = \sqrt{AO^2 + OB^2}$

$\sf \longrightarrow \sqrt{12^2 + 5^2}$

$\sf \longrightarrow \sqrt{ 144 + 25}$

$\sf \longrightarrow \sqrt{169}$

$\sf \longrightarrow 13 \: cm$

⇒ Now, we can find the Perimeter.

$\sf \longrightarrow Perimeter \: of \: Rhombus = 4 \times 13$

$\sf \longrightarrow 52$

$\sf \longrightarrow 52 \: cm$

• Therefore, the perimeter of special parallelogram rhombus is 52 cm.

✳ [For better understanding check the attachment.]