The lengths of four conducting wires are in the ratio 1:2:3:4. All wires are of same material and same radius. if they are connected in parallel with a battery .then the ratio of currents in these wires will be : brief explanation is Brainliest
Answers
let the values be X
x:2x:3x:4x
adding the values
10x=28*10^7
(velocity of electrical current)
x=28*10^6
x=28x10 power 6
2x=56x10 power 6
3x=84x10 power 6
4x=4*28*10 power 6
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Answer:
Explanation: Let the ratio of the lengths be x : 2x : 3x : 4x
R = ρl / A
R - Resistance
ρ - Resistivity
l - Length of wire
A - Area of cross section of wire
Since they have the same radii and are made of the same material, they have the same area of cross section and resistivity.
R₁ = ρx / A
R₂ = 2ρx / A Therefore, ratio of resistance is
R₃ = 3ρx / A x : 2x : 3x : 4x
R₄ = 4ρx / A
In a parallel circuit, the voltage remains constant and current splits.
By Ohm's Law, I = V/R
I₁ = V/R₁ = VA/ρx
I₂ = V/R₂ = VA/2ρx
I₃ = V/R₃ = VA/3ρx
I₄ = V/R₄ = VA/4ρx
Now, I₁ : I₂ : I₃ : I₄ = VA/ρx : VA/2ρx : VA/3ρx : VA/4ρx
= 1 : 1/2 : 1/3 : 1/4