Question

The lengths of four conducting wires are in the ratio 1:2:3:4. All wires are of same material and same radius. if they are connected in parallel with a battery .then the ratio of currents in these wires will be : brief explanation is Brainliest​

Answer 1

let the values be X

x:2x:3x:4x

adding the values

10x=28*10^7

(velocity of electrical current)

x=28*10^6

x=28x10 power 6

2x=56x10 power 6

3x=84x10 power 6

4x=4*28*10 power 6

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Answer 2

Answer:

Explanation: Let the ratio of the lengths be x : 2x : 3x : 4x

                     R = ρl / A

                     R - Resistance

                     ρ - Resistivity

                      l - Length of wire

                      A - Area of cross section of wire                              

                     Since they have the same radii and are made of the   same material, they have the same area of cross section and resistivity.

R₁ = ρx / A

R₂ = 2ρx / A                               Therefore, ratio of resistance is

R₃ = 3ρx / A                               x : 2x : 3x : 4x  

R₄ = 4ρx / A

In a parallel circuit, the voltage remains constant and current splits.

By Ohm's Law, I = V/R

I₁ = V/R₁ = VA/ρx

I₂ = V/R₂ = VA/2ρx

I₃ = V/R₃ = VA/3ρx

I₄ = V/R₄ = VA/4ρx

Now, I₁ : I₂ : I₃ : I₄ = VA/ρx : VA/2ρx : VA/3ρx : VA/4ρx

                            = 1 : 1/2 : 1/3 : 1/4