Math, asked by jeonjungkookslover, 1 month ago

The lengths of sides of a triangle are in the ratio 3: 3: 4 and its perimeter is 120 cm, find its area.​

Answers

Answered by Anonymous
0

Answer:

Given, Side of triangle are in ratio 3:4:5 and their perimeter 144 cm.

Let the sides of triangle be 3x,4x,5x

Perimeter =3x+4x+5x=120 cm

12x=120

∴x=10

Then sides of triangle are 3x=3×10= 30 cm,

4x=4×10=40 cm,

5x=5×10=50 cm.

Now, Semi perimeter, s=

2

Sum of sides of triangle

=

2

30+40+50=120/2=60

= 60cm

Using Heron's formula, Area of triangle =

s(s−a)(s−b)(s−c)

= Root over

60(60−30)(60−40)(60−50)

=

Root over 60×30×20×10

=600cm

Answered by adharvb20
0

Answer

step by step explanation :

by herons formula

√s(s-a)(s-b)(s-c)

( In this S= semiperimeter and a, b, c are sides of triangle)

seniperimeter = Perimeter /2

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