The lengths of sides of a triangle are in the ratio 3:4:5 and ots perimeter is 120cm find its area
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Ratio of sides
3:4:5
Now,
3x+4x+5x= 120
12x= 120
x=10cm
Now ,we can compute sides of triangle
30cm,40cm,50cm
Clearly it is a right angled triangle
So,
Hieght =40cm
Base = 30 cm
Area of Triangle= 1/2*Base*Height
=1/2*30*40
=600cm²
3:4:5
Now,
3x+4x+5x= 120
12x= 120
x=10cm
Now ,we can compute sides of triangle
30cm,40cm,50cm
Clearly it is a right angled triangle
So,
Hieght =40cm
Base = 30 cm
Area of Triangle= 1/2*Base*Height
=1/2*30*40
=600cm²
Answered by
8
Heya!!
Here is your answer :
Let the three sides be 3x , 4x and 5x respectively.
3x + 4x + 5x = 120 cm
12x = 120 cm
x = 10 cm
The sides are of lenght
30 cm, 40 cm and 50 cm
From here we can clearly see that the given triangle is a right angled triangle.
So, it's area is given by
1/2 × 30 × 40
= 600 cm^2
Hope it helps you : )
Here is your answer :
Let the three sides be 3x , 4x and 5x respectively.
3x + 4x + 5x = 120 cm
12x = 120 cm
x = 10 cm
The sides are of lenght
30 cm, 40 cm and 50 cm
From here we can clearly see that the given triangle is a right angled triangle.
So, it's area is given by
1/2 × 30 × 40
= 600 cm^2
Hope it helps you : )
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