Question

The lengths of sides of a triangular field are 28m,15m,41m. The area of the field , when the cost of levelling the field at the rate of RS 20 per sq m is ​

Answer 1

Given:-

• Length of triangle 28m , 15m & 41m

To Find:-

• cost of levelling the field at the rate of RS 20 m².

Solution:-

Firstly we calculate the area of triangular field .

Using Heron's Formula

→ S1 = 41m , S2 = 28m ,S3 = 15m

•S = Sum of lengths of triangle /2

→ s = 28+41+15/2

→ s = 84/2

→ s = 42 m

Now, Area

$\: \: \: \: = \sqrt{(s - s1)(s - s2)(s - s3)} \\ \\ \: \: \ \: \: \: \: \: \: \: = \sqrt{(42 - 41)(42 - 28)(42 - 15)} \\ \\ \\ \: = \sqrt{(1)(14)(27)} \\ \\ = {378} \\ \: \: \: \: \: \: \: \: \: \\ = 19.44 {m}^{2}$

Therefore, the area of the triangular field is 19.44m².

Now, Cost of levelling the field at per m² is Rs20

→ 19.44 × 20

→ 194.4 ×2

→Rs 388.8

Therefore, Total cost of levelling the field is Rs 388.8 .

Answer 2

$\huge\star\large{\mathbb{\pink{question:-}}}$

The lengths of sides of a triangular field are 28m,15m,41m. The area of the field , when the cost of levelling the field at the rate of RS 20 per sq m is 

$\huge \star\large{\mathbb{\pink{ANSWER:-}}}$

$\bf area \: of \: the \: field \:$

Using Heron's Formula

$\bf \begin{gathered}\: \: \: \: = \sqrt{(s - s1)(s - s2)(s - s3)} \\ \\ \: \: \ \: \: \: \: \: \: \: = \sqrt{(42 - 41)(42 - 28)(42 - 15)} \\ \\ \\ \: = \sqrt{(1)(14)(27)} \\ \\ = {378} \\ \: \: \: \: \: \: \: \: \: \\ = 19.44 {m}^{2}\end{gathered}$

☞So, the area of the field is 19.44m².

➜After that Cost the field at per m² is Rs20

19.44 × 20

194.4 ×2

Rs 388.8

, Total cost of field is Rs 388.8