the lengths of sides of triangle are x, x+1, x+2 .find the value of x.
if the given triangle is right angled triangle
Answers
Answer:
The sides of a right triangle are x, x + 1 and x + 2. Using Pythagoras' Theorem, (x + 2)^2 = (x + 1)^2 + x^2
=> x^2 + 4x + 4 = x^2 + 2x + 1 + x^2
=> x^2 - 2x - 3 = 0
=> x^2 - 3x + x - 3 = 0=> (x + 1)(x - 3) = 0
=> x = -1 and x = 3
The length of a side cannot be negative, ignore x = -1.
The length of the sides of the right triangle are 3, 4 and 5
✬ Sides = 3 , 4 and 5 ✬
Step-by-step explanation:
Given:
- Length of sides of triangle are x , x + 1 , x + 2.
To Find:
- What is the value of x ?
Solution: Since, it is right angled triangle. So we by using Pythagoras Theorem
★ H² = B² + P² ★
- Longest side (x + 2) will be Hypotenuse.
(x + 2)² = x² + (x + 1)²
x² + 2² + 2•x•2 = x² + x² + 1² + 2•x•1
x² + 4 + 4x = x² + x² + 1 + 2x
x² – x² – x² + 4 – 1 = 2x – 4x
– x² + 3 = – 2x
0 = x² – 2x – 3
Solving this equation by middle term splitting method.
➨ x² – 2x – 3
➨ x² – 3x + x – 3
➨ x(x – 3) + 1 (x – 3)
➨ (x + 1) and (x – 3)
➨ x + 1 = 0 or x – 3 = 0
➨ x = – 1 or x = 3
[ We have to take the positive value of x i.e 3 ]
So, Measure of sides are
- x = 3
- x + 1 = 3 + 1 = 4
- x + 2 = 3 + 2 = 5
_____________
★ Verification ★
➭ 5² = 4² + 3²
➭ 25 = 16 + 9
➭ 25 = 25