Question

the lengths of the diagonal of a rhombus are30cm and40cm.find the side of the rhombus

Answer 1

It is known that the diagonals of a rhombus are perpendicular to each other

∴ ∠AOB = 90°

Using Pythagoras theorem in ∆AOB

AB2 = OA2 + OB2 = (15 cm)2 + (20 cm)2 = (225 + 400) cm2 = 625 cm2 = (25 cm)2

⇒AB = 25 cm

Thus, the side of the rhombus is 25 cm

 

Hope! This will help you.

Answer 2

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Here is the solution:

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The diagonals of rhombus bisect at right angle

⇒ 1/2 the length of diagonal and a side forms a right angle triangle

Find 1/2 of each of the diagonals:

diagonal 1 = 30 ÷ 2 = 15 cm

diagonal 2 = 40 ÷ 2 = 20 cm

Use Pythagoras' theorem to find the side of the rhombus:

a² + b² = c²

15² + 20²= c²

c² = 625

c = √625

c = 25 cm

Answer: The side of the rhombus is 25 cm