Question

The lengths of the diagonals AC and BD of a rhombus are 6cm and 8cm. Find

the length of each side of the rhombus. Also, find its area.​

Answer 1

PROPERTY'S USED

● DIAGONAL OF RHOMBUS BISECT EACH OTHER AT 90°

● DIAGONAL OF RHOMBUS BISECT EACH OTHER EQUALLY.

Answer 2

Answer:let cross section point of AC and BD be O

so since we know that in rhombus diagonal are perpendicular bisector

so AO= 3 and BO = 4 so

$AO^{2} + BO^{2} = AB^{2}$                        (pythagoras theorem)

so $3^{2} + 4^{2} = AB^{2}$

$9 + 16 = AB^{2}$

$25=AB^{2}$

5=AB

since each of rhombus is equal

area of rhombus = 1/2 *D₁*D₂

area of ABCD  = 1/2*6*8

area of ABCD = 3*8

Area of ABCD = 24

Step-by-step explanation:

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