Question

the lengths of the diagonals of a rhombus are 1. 16 cm and 12cm by pythegoras theorum​

Answer 1

⇒ Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm.

⇒  We know that the diagonals of rhombus bisect at right angles.

⇒  AO=216=8cm

⇒  BO=212=6cm

⇒  In right angled △AOB,

By using Pythagoras theorem,

⇒  AB2=AO2+BO2

⇒  AB2=82+62

⇒  AB2=64+36

⇒  AB2=100

⇒  AB=100 

⇒  AB=10cm

∴  Side of a rhombus is 10cm.