the lengths of the diagonals of a rhombus are 10cm and 24 cm. the length of each side of the rhombus is=_________________________.
please tell me the answer ASAP along with the process.
thankyou.
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diagonal will intersect at there mid point
there one will be divided into 5+5
& other will 12+12
then rombus diagonal intersect at right angle
therefore, 12;5;13 are phythagorian triplets
and the other side will be 13
there one will be divided into 5+5
& other will 12+12
then rombus diagonal intersect at right angle
therefore, 12;5;13 are phythagorian triplets
and the other side will be 13
Answered by
2
let d1 = 10 cm
d2 = 24 cm
half of d1 = 5 cm = a
half of d2 = 12 cm = b
the diagonals of a rhombus are perpendicular to each other, therefore,
a, b and the side of the rhombus form right angled triangle.
by pythagoras theorem,
a² + b²= side²
5² + 12² = side²
25+144=side²
169=side²
side=13
d2 = 24 cm
half of d1 = 5 cm = a
half of d2 = 12 cm = b
the diagonals of a rhombus are perpendicular to each other, therefore,
a, b and the side of the rhombus form right angled triangle.
by pythagoras theorem,
a² + b²= side²
5² + 12² = side²
25+144=side²
169=side²
side=13
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